Spardha-2012

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Postulates and Theorems of Boolean Algebra :)

 Postulates and Theorems of Boolean Algebra 

Duality Principle:

This property of Boolean algebra state that all binary expressions remain valid when following two steps are performed


Using Boolean algebra techniques, the expression may be significantly simplified:

 Assume A, B, and C are logical states that can have the values 0 (false) and 1 (true)."+" means OR, "·" means AND, and ^NOT[A] means NOT A

 Postulates 

(1)	A + 0 = A	A · 1 = A	identity
(2)	A + NOT[A] = 1	A · NOT[A] = 0	complement
(3)	A + B = B + A	A · B = B · A	commutative law
(4)	A + (B + C) = (A + B) + C	A · (B · C) = (A · B) · C	associative law
(5)	A + (B · C) = (A + B) · (A + C)	A · (B + C) = (A · B) + (A · C)	distributive law

Theorems 

(6)	A + A = A	A · A = A
(7)	A + 1 = 1	A · 0 = 0
(8)	A + (A · B) = A	A · ( A + B) = A
(9)	A + (NOT[A] · B) = A + B	A · (NOT[A] + B) = A · B
(10)	(A · B) + (NOT[A] · C) + (B · C) = (A · B) + (NOT[A] · C)	A · (B + C) = (A · B) + (A · C)
(11)	NOT[A + B] = NOT[A] · NOT[B]	NOT[A · B] = NOT[A] + NOT[B]	De Morgan's theorem

Cope and Robbers!

<div><a href="http://www.shegame.com/view/9473/Cops and Robbers"><img src="http://www.shegame.com/flash_games/images/copsandrobbers.jpg" width="180" height="135" border="0" alt="" /></a><br /><a href="http://www.shegame.com/view/9473/Cops and Robbers">Cops and Robbers</a></div>

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Myself, Raymond Joshua studying in St.Joseph's Indian Composite PU College  (SJICPUC)  1st Year PCMC, Very glad to let you Josephites know that this blog is and for only you Josephites.Any latest or hot news will be published here.(including model papers,key answers,etc)

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 Raymond (Joe)